c'apps Answer Pl check our answer and correct 

Answer:   SomeGarbagevalue---10

Explanation:

In this 3-dimensional array maximal index values are

1.       expression  &p[2][2][2] address the element far beyond the array area. It is a programmers error, although the compiler does not check it. The system may indicate it as general protection error.

              ***a is just first element of the array (type int), but *q is defererencing uninitialized pointer, the value would be stored in some random memory cell, which is the second serious error of the

 same type : memory allocation

Answer :    50

Explanation:

        The preprocessor directives can be redefined anywhere in the program. So the most recently assigned value will be taken

 Answer:

sizeof(void *)=2

sizeof(int *)=2

sizeof(double *)=2

sizeof(struct unknown *)=2

Explanation:

The pointer to any type is of same size.

Answer:  64

Explanation:

               The macro call squre(4) will substituted by 4*4 so the expression becomes i=64/4*4.since / and* has equal priority the expression will be evaluated as(64/4)*4    i.e. 16*4=64 

Answer:    c=2;

Explanation:

      Here unary minus(or negation operator is used twice. Same maths rules applies, ie. Minus * minus=plus.

Note:

       However you cannot give like --2.  Because -- operator can only be applied to variables as a decrement operator (eg., i--). 2 is a constant and not a variable.

  

 

Answer:

1111

2424

3737

4242

5555

6868

7373

8686

9999

Explanation:

      *(*(p+i)+j) is equivalent to p[i][j].

P+I andi+p mean the same, although it is very rarely used

 Answer:

H

Explanation:

* is a dereference operator & is a reference operator. They can be applied any number of times provided it is meaningful

 Answer:  10

 Explanation:

                     he size of integer array of 10 elements is 10 * sizeof(int). The macro expands to                       

                       sizeof(arr)/sizeof(int) => 10 * sizeof9int)/sizeof =>10.

Answer :    1 2

        Explanation: The sizeof() operator gives the number of bytes taken by its operand. P is a Character pointer, which needs one byte for storing its value(a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2. 

Answer: Infinite loop

        Explanation:

                  The difference between the previous question and this one is that the char is declared to be unsigned. So the i++ can never yield negative value and i>=0 Never  becomes  false so that it can come out of the for loop